(n^2+4n+4)-(n^2+2n+1)=-11

Solution for (n^2+4n+4)-(n^2+2n+1)=-11 equation:

Simplifying
(n2 + 4n + 4) + -1(n2 + 2n + 1) = -11

Reorder the terms:
(4 + 4n + n2) + -1(n2 + 2n + 1) = -11

Remove parenthesis around (4 + 4n + n2)
4 + 4n + n2 + -1(n2 + 2n + 1) = -11

Reorder the terms:
4 + 4n + n2 + -1(1 + 2n + n2) = -11
4 + 4n + n2 + (1 * -1 + 2n * -1 + n2 * -1) = -11
4 + 4n + n2 + (-1 + -2n + -1n2) = -11

Reorder the terms:
4 + -1 + 4n + -2n + n2 + -1n2 = -11

Combine like terms: 4 + -1 = 3
3 + 4n + -2n + n2 + -1n2 = -11

Combine like terms: 4n + -2n = 2n
3 + 2n + n2 + -1n2 = -11

Combine like terms: n2 + -1n2 = 0
3 + 2n + 0 = -11
3 + 2n = -11

Solving
3 + 2n = -11

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2n = -11 + -3

Combine like terms: 3 + -3 = 0
0 + 2n = -11 + -3
2n = -11 + -3

Combine like terms: -11 + -3 = -14
2n = -14

Divide each side by '2'.
n = -7

Simplifying
n = -7